Let P be an interior point of ΔABC such that 4−−→PA+3−−→P – InterviewSolution

1.	Let P be an interior point of ΔABC such that 4−−→PA+3−−→PB+5−−→PC=0. If Area(ΔABC)=k×Area(ΔAPC), then k is
Answer» Let $P$ be an interior point of $Δ A B C$ such that $4 - - \to P A + 3 - - \to P B + 5 - - \to P C = 0$ . If $Area (Δ A B C) = k \times Area (Δ A P C)$ , then $k$ is

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