Let P be a plane, which contains the line of intersection of the plane – InterviewSolution

1.	Let P be a plane, which contains the line of intersection of the planes, x+y+z−6=0 and 2x+3y+z+5=0 and it is perpendicular to the xy-plane. Then the distance of the point (0,0,256) from P is equal to :
Answer» Let $P$ be a plane, which contains the line of intersection of the planes, $x + y + z - 6 = 0$ and $2 x + 3 y + z + 5 = 0$ and it is perpendicular to the $x y$ -plane. Then the distance of the point $(0, 0, 256)$ from $P$ is equal to :

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