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Let P and Q be the points of trisection of the line segment joining the points A (2, -2) and B (-7, 4) such that P is nearer to A. Find the coordinates of P and Q. |
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Answer» Given : P and Q be the points of TRISECTION of the line segment joining the points A (2, -2) and B (-7, 4) such that P is nearer to A. To Find : the coordinates of P and Q Solution: A (2, -2) and B (-7, 4) P and Q be the points of trisection AP = PQ = QB AP + PQ + QB = AB => AP : PB = 1 : 2 PQ = QB => Q is the mid point of PB AP : PB = 1 : 2 => P divides AB internally in 1 :2 ratio A (2, -2) and B (-7, 4) => P = ( 1 * - 7 + 2 * 2)/3 . ( 1*4 + 2 * - 2)/3 => P =( - 1, 0) P =( - 1, 0) B (-7, 4) Q = ( - 1 - 7)/2 , (0 + 4)/2 => Q = - 4 , 2 P =( - 1, 0) Q = (-4,2) Learn More: Points P and Q trisect the line segment joining the points A(-2,0) and ... the given FIGURE P and Q trisect the line segment bc of triangle ABC ... |
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