Let P=50∑r=150+rCr(2r−1)50Cr(50+r), Q=50∑r=0(50Cr)2 and R=100∑ – InterviewSolution

1.	Let P=50∑r=150+rCr(2r−1)50Cr(50+r), Q=50∑r=0(50Cr)2 and R=100∑r=0(−1)r(100Cr)2. Then
Answer» Let $P = 50 \sum r = 1 \frac{^{50 + r} C_{r} (2 r - 1)}{^{50} C_{r} (50 + r)}, Q = 50 \sum r = 0 (^{50} C_{r})^{2}$ and $R = 100 \sum r = 0 (- 1)^{r} (^{100} C_{r})^{2}$ . Then

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