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Let O(0, 0), P(3, 4), Q(6, 0) be the vertices of the triangle OPQ. The point R lies inside the ΔOPQ such that the triangles OPR, PQR, OQR are of equal area. The coordinates of R are(A) (4/3, 3)(B) (3, 2/3)(C) (3, 4/3)(D) (4/3, 2/3) |
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Answer» Correct option (C) (3, 4/3) Explanation : A point inside a triangle divides the triangle into three triangles of equal areas if and only if the point is the centroid of the triangle. Hence, R must be the centroid of ΔOPQ. Therefore R(0 + 3 + 6/3 , 0 + 4 + 0/3) = (3,4/3) |
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