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Let n∈N and [x] denote the greatest integer less than or equal to x. If the sum of (n+1) terms nC0, 3⋅nC1, 5⋅nC2, 7⋅nC3,… is equal to 2100⋅101, then 2[n−12] is equal to

Answer» Let nN and [x] denote the greatest integer less than or equal to x. If the sum of (n+1) terms nC0, 3nC1, 5nC2, 7nC3, is equal to 2100101, then 2[n12] is equal to


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