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Let n be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that all the girls stand consecutively in the queue. Let m be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that exactly four girls stand consecutively in the queue. Then the value of m/n is__ |
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Answer» n = 6!·5! (5 girls together arranged along with 5 boys) m = 5C4 .(7! -2.6! 4!). 4! (4 out of 5 girls together arranged with others – number of cases all 5 girls are together) m/n = 5.5 .6! .4! / 6!. 5! = 5 |
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