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Let n be an integer greater than 100 such that the L.C.M. of 1, 2, 3, … n is equal to the L.C.M. of 101, 102 ,…, n. Find the product of all digits of the smallest possible value of n. |
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Answer» Given : n be an integer greater than 100 such that the L.C.M. of 1, 2, 3, … n is equal to the L.C.M. of 101, 102 ,…, n. To find : the product of all DIGITS of the smallest possible value of n. Solution: L.C.M. of 1, 2, 3, … n is equal to the L.C.M. of 101, 102 ,…, n. Let find prime number less than 101 that is 97 So LCM of 101, 102 ,…, n. must have a number having a number multiple of 97 97 * 2 = 194 hence n should be atleast 194 product of all digits of the smallest possible value of n = 1 * 9 * 4 = 36 Learn More: find the LCM AND hcf of (m2-2m-15), (m3-125-15m2+75m) and (m2 ... |
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