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Let n be a positive integer. Let A=n∑k=0(−1)k nCk[(12)k+(34)k+(78)k+(1516)k+(3132)k]. If 63A=1−1230, then n is equal to

Answer» Let n be a positive integer. Let A=nk=0(1)k nCk[(12)k+(34)k+(78)k+(1516)k+(3132)k]. If 63A=11230, then n is equal to


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