Let L1=limx→0cos(πx)(eλx−1)πsinx and L2=limx→0ln(1−x)+sin2x – InterviewSolution

1.	Let L1=limx→0cos(πx)(eλx−1)πsinx and L2=limx→0ln(1−x)+sin2xx. If L1=L2, then the value of [λ] is (Note: [λ] denotes the largest integer less than or equal to λ.)
Answer» Let $L_{1} = lim x \to 0 \frac{cos (π x) (e^{λ x} - 1)}{π sin x}$ and $L_{2} = lim x \to 0 \frac{ln (1 - x) + sin 2 x}{x}$ . If $L_{1} = L_{2}$ , then the value of $[λ]$ is (Note: $[λ]$ denotes the largest integer less than or equal to $λ$ .)

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