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Let K is any three digit number which is perfect square and perfect cube both where k, 600 < K < 750 then what will be the sum of digits of K?1. 182. 203. 174. 15 |
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Answer» Correct Answer - Option 1 : 18 Given: It is given that K is three digit number where k, 600 < K < 750 Calculation: Let suppose the number is 9 ∴ 9 × 9 × 9 = 729, perfect cube Now, consider the expression again ∴ 9 × 9 × 9 = (9 × 3) × (3 × 9) = 27 × 27 = 729, perfect square Now, sum of digits ∴ 7 + 2 + 9 = 18 Hence, option (1) is correct |
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