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Let `g(x)=int_0^x f(t).dt`,where f is such that `1/2 |
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Answer» `g(x)=int_0^2f(x)dt=int_0^1f(x)dt+int_1^2f(x)dt` `Ain(0,1)` `int_0^1 1/2dx<=int_0^1f(t)dt<=int_0^1dt` `1/2<=int_0^1f(t)dt<=1-(1)` `Ain(1,2)` `int_1^2dt<=int_1^2f(t)dt<=int_1^2 1/2dx` `0<=int_1^2f(t)dt<=1/2-(2)` adding equation 1 and 2 `1/2<=g(2)<=3/2` option 2 is correct. |
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