Let g:R→[0,π3] be a function defined by g(x)=cos−1(x2−k1+x2). I – InterviewSolution

1.	Let g:R→[0,π3] be a function defined by g(x)=cos−1(x2−k1+x2). If the absolute value of k for which g is surjective function is 1a, then the value of a is
Answer» Let $g : R \to [0, \frac{π}{3}]$ be a function defined by $g (x) = {cos}^{- 1} (\frac{x^{2} - k}{1 + x^{2}})$ . If the absolute value of $k$ for which $g$ is surjective function is $\frac{1}{a}$ , then the value of $a$ is

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