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Let `f: X -> Y`be an invertible function. Show that the inverse of `f^(-1)`is f, i.e., `(f^(-1))^(-1)= f`. |
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Answer» `because f : X to Y ` is an invertible function. ` therefore g : Y to X` will be a function such that `" " gof = I_X and fog = I_Y` `rArr " " f^(-1) = g ` Now `" " gof = I_X and fog = I_Y` `rArr " " f^(-1) of = I_X and fof ^(-1) = I_Y` `rArr f^(-1) : Y to X ` will be invertible and `(f^(-1))^(-1) = f ` |
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