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Let f(x)=⎧⎪⎨⎪⎩(x−1)12−x ,x>1,x≠2k ,x=2 The value of k for which f is continuous at x=2 is : |
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Answer» Let f(x)=⎧⎪⎨⎪⎩(x−1)12−x ,x>1,x≠2k ,x=2 |
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