Let f(x)=sin−1(2x√1−x2). If 1√2<x<1, then f′(x)= – InterviewSolution

1.	Let f(x)=sin−1(2x√1−x2). If 1√2<x<1, then f′(x)=
Answer» Let $f (x) = {sin}^{- 1} (2 x \sqrt{1 - x^{2}}) .$ If $\frac{1}{\sqrt{2}} < x < 1,$ then $f^{'} (x) =$

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