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Let ∫f′(x)g(x)−g′(x)f(x)(f(x)+g(x))√f(x)g(x)−(g(x))2dx=√mtan−1(√f(x)−g(x)ng(x))+C, where m,n∈N, C is constant of integration and g(x)>0.. Then the value of (m2+n2) is

Answer» Let f(x)g(x)g(x)f(x)(f(x)+g(x))f(x)g(x)(g(x))2dx=mtan1(f(x)g(x)ng(x))+C, where m,nN, C is constant of integration and g(x)>0.. Then the value of (m2+n2) is


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