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Let `f: Rvec[0,pi/2)`be defined by `f(x)=tan^(-1)(x^2+x+a)dot`Then the set of values of `a`for which `f`is onto is`(0,oo)`(b) `[2,1]`(c) `[1/4,oo]`(d) none of theseA. `[0,oo)`B. `[2,1]`C. `[(1)/(4),oo)`D. none of these |
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Answer» Correct Answer - C Since co-domain`=[0,(pi)/(2))` This is possible only when `x^(2) +x+a` is perfect square. ` :. 1-4a=0 " or " a=(1)/(4)` |
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