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Let f:R→R be a function which satisfies f(x+y)=f(x)+f(y) ∀x,y∈R. If f(1)=2 and g(n)=(n−1)∑k=1 f(k),n∈N then the value of n, for which g(n)=20, is: |
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Answer» Let f:R→R be a function which satisfies f(x+y)=f(x)+f(y) ∀x,y∈R. If f(1)=2 and g(n)=(n−1)∑k=1 f(k),n∈N then the value of n, for which g(n)=20, is: |
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