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Let f:R→R be a differentiable function such that its derivative f′ is continuous and f(π)=−6. If F:[0,π]→R is defined by F(x)=x∫0f(t)dt, and if π∫0(f′(x)+F(x))cosx dx=2, then the value of f(0) is

Answer» Let f:RR be a differentiable function such that its derivative f is continuous and f(π)=6. If F:[0,π]R is defined by F(x)=x0f(t)dt, and if π0(f(x)+F(x))cosx dx=2, then the value of f(0) is


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