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Let f:R→R be a differentiable function such that f(x)=x2+x∫0e−tf(x−t)dt. Then, the value of 1∫0f(x)dx is |
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Answer» Let f:R→R be a differentiable function such that f(x)=x2+x∫0e−tf(x−t)dt. Then, the value of 1∫0f(x)dx is |
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