Let f:R→R be a differentiable function such that f(0)=0, f(π2)=3 an – InterviewSolution

1.	Let f:R→R be a differentiable function such that f(0)=0, f(π2)=3 and f′(0)=1. If g(x)=π2∫x[f′(t)cosec t−cott cosec t f(t)]dtfor x∈(0,π2], then limx→0g(x)=
Answer» Let $f : R \to R$ be a differentiable function such that $f (0) = 0, f (\frac{π}{2}) = 3 and f^{'} (0) = 1. If g (x) = \frac{π}{2} \int x [f^{'} (t) cosec t - cot t cosec t f (t)] d t for x \in (0, \frac{π}{2}], then lim x \to 0 g (x) =$

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