Let f, g: R → R be defined respectively, and f(x) = x2 - 12x + 32, g

1.	Let f, g: R → R be defined respectively, and f(x) = x2 - 12x + 32, g(x) = x -3. Find f o g (1).1. 302. 403. 504. 60
Answer» Correct Answer - Option 4 : 60 CONCEPT: Let f: A → B and g: B → C be two functions. Then, the composition of f and g, denoted by g o f, is defined as the function g o f: A → C given by g o f (x) = g (f (x)), ∀ x ∈ A. CALCULATIONS: Given functions are f(x) = x ²- 12x + 32, g(x) = x -3. f o g means g(x) function is in f(x) function. This means put x = x -3 in function f(x). f[g(x)] = (x - 3) ² - 12(x -3) + 32 f[g(x)] = x² – 18x + 77 now we have to find f o g (1). ∴ f [g (1)] = 1² – 18+ 77 = 60

Let f, g: R → R be defined respectively, and f(x) = x2 - 12x + 32, g(x) = x -3. Find f o g (1).1. 302. 403. 504. 60

Answer» Correct Answer - Option 4 : 60

CONCEPT:

Let f: A → B and g: B → C be two functions. Then, the composition of f and g, denoted by g o f, is defined as the function g o f: A → C given by g o f (x) = g (f (x)), ∀ x ∈ A.

CALCULATIONS:

Given functions are f(x) = x ²- 12x + 32, g(x) = x -3.

f o g means g(x) function is in f(x) function.

This means put x = x -3 in function f(x).

f[g(x)] = (x - 3) ² - 12(x -3) + 32

f[g(x)] = x² – 18x + 77

now we have to find f o g (1).

∴ f [g (1)] = 1² – 18+ 77 = 60

Discussion

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