1.

Let f be defined on [0, 1] be twice differentiable such that |f"(x)|

Answer» Let f be defined on [0, 1] be twice differentiable such that |f"(x)| <= 1 for all x belongs to [0, 1]. If f(0) = f(1), then show that |f'(x)| < 1 for all x belongs to [0, 1].


Discussion

No Comment Found