Let f be a twice differentiable function on R such that t2f(x)−2tf� – InterviewSolution

1.	Let f be a twice differentiable function on R such that t2f(x)−2tf′(x)+f′′(x)=0 has two equal values of t for all x and f(0)=1,f′(0)=2. Then the value of 3limx→0(f(x)−1x−t2) is
Answer» Let $f$ be a twice differentiable function on $R$ such that $t^{2} f (x) - 2 t f^{'} (x) + f^{''} (x) = 0$ has two equal values of $t$ for all $x$ and $f (0) = 1, f^{'} (0) = 2.$ Then the value of $3 lim x \to 0 (\frac{f (x) - 1}{x} - \frac{t}{2})$ is

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