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Let `f: A to B` and `g: B to C` be two functions. Then; if gof is onto then g is onto; if gof is one one then f is one-one and if gof is onto and g is one one then f is onto and if gof is one one and f is onto then g is one one. |
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Answer» Let `z in D,` then there is some `y in C` such that `g(y)=z` ` :.` Now if `y notin B`, then there is no x for which `f(x)=y` ` :. gof` is not onto. |
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