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Let F:[3,5]→R be a twice differentiable function on (3, 5) such that F(x)=e−xx∫3(3t2+2t+4F′(t))dt. If F′(4)=αeβ−224(eβ−4)2, then α+β is equal to

Answer» Let F:[3,5]R be a twice differentiable function on (3, 5) such that F(x)=exx3(3t2+2t+4F(t))dt. If F(4)=αeβ224(eβ4)2, then α+β is equal to


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