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Let `f:[-1,oo] in [-1,oo]` be a function given `f(x)=(x+1)^(2)-1, x ge -1` Statement-1: The set `[x:f(x)=f^(-1)(x)]={0,1}` Statement-2: f is a bijection.A. 1B. 2C. 3D. 4 |
| Answer» Correct Answer - A | |