Let d1,d2 be the longest and shortest distance of a point P(7,2) from the curve x2+y2−10x−14y−51=0. Then the geometric mean of d1 and d2 is equal to

Let d1,d2 be the longest and shortest distance of a point P(7,2) from

1.	Let d1,d2 be the longest and shortest distance of a point P(7,2) from the curve x2+y2−10x−14y−51=0. Then the geometric mean of d1 and d2 is equal to
Answer» Let $d_{1}, d_{2}$ be the longest and shortest distance of a point $P (7, 2)$ from the curve $x^{2} + y^{2} - 10 x - 14 y - 51 = 0.$ Then the geometric mean of $d_{1}$ and $d_{2}$ is equal to

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Let d1,d2 be the longest and shortest distance of a point P(7,2) from the curve x2+y2−10x−14y−51=0. Then the geometric mean of d1 and d2 is equal to

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