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Let* be a binary operation on `N`given bya*b = HCF`(a , b) a , b Ndot`Write thevalue of 22*4. |
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Answer» Here, `a**b = HCF(a,b) a,b in N` `:. 22**4 = HCF(22,4)` `=>22 = 2**11 and 4 = 2**2` Here, common factor is `2`. So,HCF is `2`. `:. 22**4 = 2` |
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