Let B be the centre of the circle x2+y2−2x+4y+1=0. Let the tangents – InterviewSolution

1.	Let B be the centre of the circle x2+y2−2x+4y+1=0. Let the tangents at two points P and Q on the circle intersect at the point A(3,1). Then 8⋅(area△APQarea△BPQ) is equal to
Answer» Let $B$ be the centre of the circle $x^{2} + y^{2} - 2 x + 4 y + 1 = 0$ . Let the tangents at two points $P$ and $Q$ on the circle intersect at the point $A (3, 1) .$ Then $8 \cdot (\frac{area △ A P Q}{area △ B P Q})$ is equal to

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