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let an amount of rs 47000 be divided into three parts such that three times the firat is equal to four times the second and five times the third. find the difference between the largest and the smallest parts .....its important plz answer​

Answer»

Answer:

Let the THREE NUMBERS be = x, y and z

According to the given question :-

x = 3y ...(1)

z = 5x ...(2)

We can also find that :-

3y = \TT{\frac{z}{5}}\\

y = \tt{\frac{z}{15}}\\ ...(3)

Average = 57

=》 \SF{\frac{x+y+z}{3} = 57}\\

Replace the values by (1),(2) and (3)

=》 \sf{\frac{3y+y+15y}{3} = 57}\\

=》 \sf{\frac{19y}{3} = 57}\\

=》 \sf{y = 9}

\sf{x = 3y = 27}

\sf{z = 5x = 135}



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