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Let A3BC and DE2F be four-digit numbers where each letter represents a different digit greater than 3. If the sum of the numbers is 15902, then what is the difference between the values of A and D?1. 12. 23. 34. 4 |
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Answer» Correct Answer - Option 3 : 3 Let A3BC and DE2F be four-digit numbers where each letter represents a different digit greater than 3. The sum of the numbers is 15902. Calculations : Add both the terms A3BC + DE2F = 15902 We will start from basic of adding Firstly we will add C + F C + F = 2, so C + F must be 12 so C and F can be either (5, 7) or (4, 8) as numbers are different and more than 3 Now, B + 2 = 10 So B must be 7 as the sum of C and F will give a carry of 1 for this step. Now, 3 + E = 9 So, E must be 5 as it will get 1 as carry from the sum of B + 2 Now in last step, A + D = 15 So, A and D can be (7, 8) or (9, 6) But it is given all digits are different so, A and D must be (9 or 6) as B already has the value 7. Now the difference between A and D = |9 - 6| ⇒ 3 ∴ The difference between A and D will be 3. |
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