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Let a1,a2,a3............. be terms of an AP. If (a1+a2+a3+a4...............ap)/(a1+a2+a3+a4................aq)=p^2/Q^2, THEN find the value of a6/a21. |
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Answer» Your question is a bit not clear.But what I understand showing you. Given a1,a2,a3............. be terms of an AP Let common difference is d (a1+a2+a3+a4...............ap)/(a1+a2+a3+a4................aq)=p^2/Q^2 p/2[2a1 + (p-1)d] / q/2[2a1+(q-1)d] = P2/Q2 => p[2a1 + (p-1)d] / q[2a1+(q-1)d] = P2/Q2 --------------------(1) Now a6/a21 = a1 + (6-1)d / a1 + (21-1)d => a6/a21 = a1 + 5d / a1 + 20d -------------(2) Now find the ratio using equation (1) and (2) |
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