Let A1,A2,A3,…… be squares such that for each n≥1, the length of the side of An equals the length of diagonal of An+1. If the length of A1 is 12 cm, then the smallest value of n for which area of An is less than one, is

Let A1,A2,A3,…… be squares such that for each n≥1, the length of

1.	Let A1,A2,A3,…… be squares such that for each n≥1, the length of the side of An equals the length of diagonal of An+1. If the length of A1 is 12 cm, then the smallest value of n for which area of An is less than one, is
Answer» Let $A_{1}, A_{2}, A_{3}, \dots \dots$ be squares such that for each $n \geq 1$ , the length of the side of $A_{n}$ equals the length of diagonal of $A_{n + 1}$ . If the length of $A_{1}$ is $12$ cm, then the smallest value of $n$ for which area of $A_{n}$ is less than one, is

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Let A1,A2,A3,…… be squares such that for each n≥1, the length of the side of An equals the length of diagonal of An+1. If the length of A1 is 12 cm, then the smallest value of n for which area of An is less than one, is

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