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Let `A={ theta in R|cos^(2) (sin theta)+sin^(2) (cos theta)=1}` and `B={ theta in R| cos (sin theta) sin (cos theta)=0}`. Then `A nn B`A. is the empty setB. has exactly one elementC. has more than one but finitely many elementsD. has infinitely many elements |
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Answer» Correct Answer - A for `A nn B` `cos (sin theta)=1` or `-1` & `sin (cos theta)=0` Which is not possible or `cos (sin theta)=0` & `sin (cos theta)=1` or `-1` also not possible so `A nn B` is an empty set |
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