Let →a=^i+^j+√2^k,→b=b1^i+b2^j+√2^k and →c=5^i+^j+√2^k be three vectors such that the projection vector of →b on →a is →a and (→a+→b) is perpendicular to →c, then |→b| is equal to

Let →a=^i+^j+√2^k,→b=b1^i+b2^j+√2^k and →c=5^i+^j+√2^k be

1.	Let →a=^i+^j+√2^k,→b=b1^i+b2^j+√2^k and →c=5^i+^j+√2^k be three vectors such that the projection vector of →b on →a is →a and (→a+→b) is perpendicular to →c, then \|→b\| is equal to
Answer» Let $\to a =^i +^j + \sqrt{2}^k, \to b = b_{1}^i + b_{2}^j + \sqrt{2}^k$ and $\to c = 5^i +^j + \sqrt{2}^k$ be three vectors such that the projection vector of $\to b$ on $\to a$ is $\to a$ and $(\to a + \to b)$ is perpendicular to $\to c$ , then $\| \to b \|$ is equal to

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Let →a=^i+^j+√2^k,→b=b1^i+b2^j+√2^k and →c=5^i+^j+√2^k be three vectors such that the projection vector of →b on →a is →a and (→a+→b) is perpendicular to →c, then |→b| is equal to

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