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Let →a=^i+2^j−3^k and →b=2^i−3^j+5^k. If →r×→a=→b×→r, →r⋅(α^i+2^j+^k)=3 and →r⋅(2^i+5^j−α^k)=−1, α∈R, then the value of α+|→r|2 is equal to : |
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Answer» Let →a=^i+2^j−3^k and →b=2^i−3^j+5^k. If →r×→a=→b×→r, →r⋅(α^i+2^j+^k)=3 and →r⋅(2^i+5^j−α^k)=−1, α∈R, then the value of α+|→r|2 is equal to : |
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