Let A be a unit vector along the axis of rotation of a purely rotating

1.	Let A be a unit vector along the axis of rotation of a purely rotating body and B be a unit vector along the velocity of a particle P of the body away from the axis. The values of A.B is -(a) 1 (b) -1 (c) 0 (d) None of these.
Answer» <P>*Answer ⇒ Option (C). 0* *Explanation ⇒* The unit vector A along the axis of the Rotation of the Purely ROTATING body will be Perpendicular to the Unit vector B along the Particle P of the body from its axis. Mathematically, Angle between them = θ = 90° Now, A.B = \|A\| \|B\|Cos θ [A.B is the DOT product.] = \|A\| \|B\| Cos 90° = \|A\| \|B\| 0 = 0 *Hence, the correct answer is Option (c).* Hope it helps.

Let A be a unit vector along the axis of rotation of a purely rotating body and B be a unit vector along the velocity of a particle P of the body away from the axis. The values of A.B is -(a) 1 (b) -1 (c) 0 (d) None of these.

Answer»

<P>Answer ⇒ Option (C). 0

Explanation ⇒ The unit vector A along the axis of the Rotation of the Purely ROTATING body will be Perpendicular to the Unit vector B along the Particle P of the body from its axis.

Mathematically, Angle between them = θ = 90°

Now,

A.B = |A| |B|Cos θ [A.B is the DOT product.]

= |A| |B| Cos 90°

= |A| |B| 0

= 0

Hence, the correct answer is Option (c).

Hope it helps.

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Let A be a unit vector along the axis of rotation of a purely rotating body and B be a unit vector along the velocity of a particle P of the body away from the axis. The values of A.B is -(a) 1 (b) -1 (c) 0 (d) None of these.

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