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Let a, b, c be real number (a ne 0). If alpha is a root of a^(2)x^(2)+bx +c=0, beta is a root of a^(2)x^(2) -bx-c=0 and 0 lt alpha beta, then the root of the equation (say gamma) a^(2) x^(2)+2bx+2c=0 always satisfies |
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Answer» `gamma=(ALPHA+beta)/(2)` |
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