Let →a,→b,→c are vectors such that |→a|=2,|→b|=3,|→c|=√3 and (3→a−2→b) is perpendicular to →c,(3→b−2→c) is perpendicular to →a and (3→c−2→a) is perpendicular to →b. Then the value of |→a+→b+→c|=

Let →a,→b,→c are vectors such that |→a|=2,|→b|=3,|→c|=√3

1.	Let →a,→b,→c are vectors such that \|→a\|=2,\|→b\|=3,\|→c\|=√3 and (3→a−2→b) is perpendicular to →c,(3→b−2→c) is perpendicular to →a and (3→c−2→a) is perpendicular to →b. Then the value of \|→a+→b+→c\|=
Answer» Let $\to a, \to b, \to c$ are vectors such that $\| \to a \| = 2, \| \to b \| = 3, \| \to c \| = \sqrt{3}$ and $(3 \to a - 2 \to b)$ is perpendicular to $\to c, (3 \to b - 2 \to c)$ is perpendicular to $\to a$ and $(3 \to c - 2 \to a)$ is perpendicular to $\to b .$ Then the value of $\| \to a + \to b + \to c \| =$