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Let a,b be the roots of x²-x+p=0 and c,d be the roots of x²-4x+q=0 . If a,b,c,d are in GP, then integral values of p and q will be ??????? |
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Answer» b/a=C/b=d/c=k a+b=1. a=1/(1+k) ab=p a*a*k=p. k/(k+1)'2=p. 1/k +k +2 =1/p then c+d=4. c=4/(1+k) cd=q. c*c*k=q. 16/q =1/k +k +2 16/q =1/p then q=-16 and p =-1 note 2<=k+1/k<=-2 |
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