1.

Let a,b>0 and α=^ia+4^jb+b^k and β=b^i+a^j+1b^k, then the maximum value of 202+α.β is:

Answer»

Let a,b>0 and α=^ia+4^jb+b^k and β=b^i+a^j+1b^k, then the maximum value of 202+α.β is:



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