Let A and B be two sets such that n(A)=p, n(B)=q and number of subsets of A is 56 more than that of B. If N is the number of relations from A to B, then the value of m such that the sum of the binomial coefficients in (x+y)m is N, is equal to

Let A and B be two sets such that n(A)=p, n(B)=q and number of subsets

1.	Let A and B be two sets such that n(A)=p, n(B)=q and number of subsets of A is 56 more than that of B. If N is the number of relations from A to B, then the value of m such that the sum of the binomial coefficients in (x+y)m is N, is equal to
Answer» Let $A$ and $B$ be two sets such that $n (A) = p,$ $n (B) = q$ and number of subsets of $A$ is $56$ more than that of $B .$ If $N$ is the number of relations from $A$ to $B,$ then the value of $m$ such that the sum of the binomial coefficients in $(x + y)^{m}$ is $N,$ is equal to