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Let A and B be two sets containing 3 and 6 elements respectively find the maximum and minimum number of elements in a union b |
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Answer» Maximum = 9 Given, A and B are the two sets which contains 3 and 6 elements respectively Therefore, N(A) = 3 n(B) = 6 Maximum no. of elements in AUB AUB wil be maximum when, the both A and B are DISJOINT sets To find Maximum no. of elements, we have to add the no. of elements of both sets Therefore, n(AUB) = n(A) + n(B) n(AUB) = 3+6 n(AUB) = 9 Minimum no. of elements in AUB AUB will be minimum, when A is a sub-set of B If, A C B Then, n(AUB) = 6 Hence, Maximum number of elements in AUB=9 minimum number of elements in AUB=6 |
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