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Let A and B be two points with position vector 2^i+^j−3^k and β^i+α2^j respectively such that |−−→AB|=3 then limx→β(x−α2)1x−(α+1) may be equal to: |
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Answer» Let A and B be two points with position vector 2^i+^j−3^k and β^i+α2^j respectively such that |−−→AB|=3 then limx→β(x−α2)1x−(α+1) may be equal to: |
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