Let A(9,−6),B(1,2) and C(4,4) be three points on the parabola y2=4x. – InterviewSolution

1.	Let A(9,−6),B(1,2) and C(4,4) be three points on the parabola y2=4x. The equation of the circumcircle formed by the point of intersections of the tangents at A,B and C is x2+y2+kx−ky+h=0. Then the value of k+h is
Answer» Let $A (9, - 6), B (1, 2)$ and $C (4, 4)$ be three points on the parabola $y^{2} = 4 x .$ The equation of the circumcircle formed by the point of intersections of the tangents at $A, B$ and $C$ is $x^{2} + y^{2} + k x - k y + h = 0.$ Then the value of $k + h$ is

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