1.

Let A=⎡⎢⎣630252011⎤⎥⎦ and B be the adjoint of A. Then the value of det(det(A−1)(A2B)T) is

Answer» Let A=⎡⎢⎣630252011⎤⎥⎦ and B be the adjoint of A. Then the value of det(det(A−1)(A2B)T) is


Discussion

No Comment Found