Let A={1,2,3,....,10} and f:A→A be defined as f(k)={k+1if k is oddkif k is even. Then the number of possible functions g:A→A such that gof=f is:

Let A={1,2,3,....,10} and f:A→A be defined as f(k)={k+1if k is oddki

1.	Let A={1,2,3,....,10} and f:A→A be defined as f(k)={k+1if k is oddkif k is even. Then the number of possible functions g:A→A such that gof=f is:
Answer» Let $A = {1, 2, 3, . . . ., 10}$ and $f : A \to A$ be defined as $f (k) = {\begin{matrix} k + 1 & if k is odd k & if k is even \end{matrix} .$ Then the number of possible functions $g : A \to A$ such that $g o f = f$ is: