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Let A=⎡⎢⎣1−1121−3111⎤⎥⎦ and 10B=⎡⎢⎣422−50a1−23⎤⎥⎦. If B is the inverse of A, then the value a is:

Answer» Let A=111213111 and 10B=42250a123.

If B is the inverse of A, then the value a is:


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